\(\int \frac {\cos ^2(e+f x)}{(a+b \sec ^2(e+f x))^3} \, dx\) [216]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [B] (verification not implemented)
   Sympy [F(-1)]
   Maxima [A] (verification not implemented)
   Giac [A] (verification not implemented)
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 23, antiderivative size = 201 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {(a-6 b) x}{2 a^4}+\frac {b^{3/2} \left (35 a^2+56 a b+24 b^2\right ) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{8 a^4 (a+b)^{5/2} f}+\frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (4 a+3 b) (a+4 b) \tan (e+f x)}{8 a^3 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )} \]

[Out]

1/2*(a-6*b)*x/a^4+1/8*b^(3/2)*(35*a^2+56*a*b+24*b^2)*arctan(b^(1/2)*tan(f*x+e)/(a+b)^(1/2))/a^4/(a+b)^(5/2)/f+
1/2*cos(f*x+e)*sin(f*x+e)/a/f/(a+b+b*tan(f*x+e)^2)^2+1/4*b*(2*a+3*b)*tan(f*x+e)/a^2/(a+b)/f/(a+b+b*tan(f*x+e)^
2)^2+1/8*b*(4*a+3*b)*(a+4*b)*tan(f*x+e)/a^3/(a+b)^2/f/(a+b+b*tan(f*x+e)^2)

Rubi [A] (verified)

Time = 0.37 (sec) , antiderivative size = 201, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.261, Rules used = {4231, 425, 541, 536, 209, 211} \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {x (a-6 b)}{2 a^4}+\frac {b (4 a+3 b) (a+4 b) \tan (e+f x)}{8 a^3 f (a+b)^2 \left (a+b \tan ^2(e+f x)+b\right )}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 f (a+b) \left (a+b \tan ^2(e+f x)+b\right )^2}+\frac {b^{3/2} \left (35 a^2+56 a b+24 b^2\right ) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{8 a^4 f (a+b)^{5/2}}+\frac {\sin (e+f x) \cos (e+f x)}{2 a f \left (a+b \tan ^2(e+f x)+b\right )^2} \]

[In]

Int[Cos[e + f*x]^2/(a + b*Sec[e + f*x]^2)^3,x]

[Out]

((a - 6*b)*x)/(2*a^4) + (b^(3/2)*(35*a^2 + 56*a*b + 24*b^2)*ArcTan[(Sqrt[b]*Tan[e + f*x])/Sqrt[a + b]])/(8*a^4
*(a + b)^(5/2)*f) + (Cos[e + f*x]*Sin[e + f*x])/(2*a*f*(a + b + b*Tan[e + f*x]^2)^2) + (b*(2*a + 3*b)*Tan[e +
f*x])/(4*a^2*(a + b)*f*(a + b + b*Tan[e + f*x]^2)^2) + (b*(4*a + 3*b)*(a + 4*b)*Tan[e + f*x])/(8*a^3*(a + b)^2
*f*(a + b + b*Tan[e + f*x]^2))

Rule 209

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*ArcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /;
 FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a, 0] || GtQ[b, 0])

Rule 211

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/Rt[a/b, 2]], x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 425

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_), x_Symbol] :> Simp[(-b)*x*(a + b*x^n)^(p + 1)*
((c + d*x^n)^(q + 1)/(a*n*(p + 1)*(b*c - a*d))), x] + Dist[1/(a*n*(p + 1)*(b*c - a*d)), Int[(a + b*x^n)^(p + 1
)*(c + d*x^n)^q*Simp[b*c + n*(p + 1)*(b*c - a*d) + d*b*(n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c,
d, n, q}, x] && NeQ[b*c - a*d, 0] && LtQ[p, -1] &&  !( !IntegerQ[p] && IntegerQ[q] && LtQ[q, -1]) && IntBinomi
alQ[a, b, c, d, n, p, q, x]

Rule 536

Int[((e_) + (f_.)*(x_)^(n_))/(((a_) + (b_.)*(x_)^(n_))*((c_) + (d_.)*(x_)^(n_))), x_Symbol] :> Dist[(b*e - a*f
)/(b*c - a*d), Int[1/(a + b*x^n), x], x] - Dist[(d*e - c*f)/(b*c - a*d), Int[1/(c + d*x^n), x], x] /; FreeQ[{a
, b, c, d, e, f, n}, x]

Rule 541

Int[((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^(q_.)*((e_) + (f_.)*(x_)^(n_)), x_Symbol] :> Simp[(
-(b*e - a*f))*x*(a + b*x^n)^(p + 1)*((c + d*x^n)^(q + 1)/(a*n*(b*c - a*d)*(p + 1))), x] + Dist[1/(a*n*(b*c - a
*d)*(p + 1)), Int[(a + b*x^n)^(p + 1)*(c + d*x^n)^q*Simp[c*(b*e - a*f) + e*n*(b*c - a*d)*(p + 1) + d*(b*e - a*
f)*(n*(p + q + 2) + 1)*x^n, x], x], x] /; FreeQ[{a, b, c, d, e, f, n, q}, x] && LtQ[p, -1]

Rule 4231

Int[sec[(e_.) + (f_.)*(x_)]^(m_)*((a_) + (b_.)*sec[(e_.) + (f_.)*(x_)]^(n_))^(p_), x_Symbol] :> With[{ff = Fre
eFactors[Tan[e + f*x], x]}, Dist[ff/f, Subst[Int[(1 + ff^2*x^2)^(m/2 - 1)*ExpandToSum[a + b*(1 + ff^2*x^2)^(n/
2), x]^p, x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f, p}, x] && IntegerQ[m/2] && IntegerQ[n/2]

Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{\left (1+x^2\right )^2 \left (a+b+b x^2\right )^3} \, dx,x,\tan (e+f x)\right )}{f} \\ & = \frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}-\frac {\text {Subst}\left (\int \frac {-a+b-5 b x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )^3} \, dx,x,\tan (e+f x)\right )}{2 a f} \\ & = \frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^2}-\frac {\text {Subst}\left (\int \frac {-2 \left (2 a^2-4 a b-3 b^2\right )-6 b (2 a+3 b) x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )^2} \, dx,x,\tan (e+f x)\right )}{8 a^2 (a+b) f} \\ & = \frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (4 a+3 b) (a+4 b) \tan (e+f x)}{8 a^3 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )}-\frac {\text {Subst}\left (\int \frac {-2 \left (4 a^3-12 a^2 b-25 a b^2-12 b^3\right )-2 b (4 a+3 b) (a+4 b) x^2}{\left (1+x^2\right ) \left (a+b+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{16 a^3 (a+b)^2 f} \\ & = \frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (4 a+3 b) (a+4 b) \tan (e+f x)}{8 a^3 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )}+\frac {(a-6 b) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\tan (e+f x)\right )}{2 a^4 f}+\frac {\left (b^2 \left (35 a^2+56 a b+24 b^2\right )\right ) \text {Subst}\left (\int \frac {1}{a+b+b x^2} \, dx,x,\tan (e+f x)\right )}{8 a^4 (a+b)^2 f} \\ & = \frac {(a-6 b) x}{2 a^4}+\frac {b^{3/2} \left (35 a^2+56 a b+24 b^2\right ) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{8 a^4 (a+b)^{5/2} f}+\frac {\cos (e+f x) \sin (e+f x)}{2 a f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (2 a+3 b) \tan (e+f x)}{4 a^2 (a+b) f \left (a+b+b \tan ^2(e+f x)\right )^2}+\frac {b (4 a+3 b) (a+4 b) \tan (e+f x)}{8 a^3 (a+b)^2 f \left (a+b+b \tan ^2(e+f x)\right )} \\ \end{align*}

Mathematica [A] (verified)

Time = 4.49 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.78 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {4 (a-6 b) (e+f x)+\frac {b^{3/2} \left (35 a^2+56 a b+24 b^2\right ) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a+b}}\right )}{(a+b)^{5/2}}+a \left (2+\frac {13 a b^2}{(a+b)^2 (a+2 b+a \cos (2 (e+f x)))}+\frac {2 b^3 (3 a+8 b+5 a \cos (2 (e+f x)))}{(a+b)^2 (a+2 b+a \cos (2 (e+f x)))^2}\right ) \sin (2 (e+f x))}{8 a^4 f} \]

[In]

Integrate[Cos[e + f*x]^2/(a + b*Sec[e + f*x]^2)^3,x]

[Out]

(4*(a - 6*b)*(e + f*x) + (b^(3/2)*(35*a^2 + 56*a*b + 24*b^2)*ArcTan[(Sqrt[b]*Tan[e + f*x])/Sqrt[a + b]])/(a +
b)^(5/2) + a*(2 + (13*a*b^2)/((a + b)^2*(a + 2*b + a*Cos[2*(e + f*x)])) + (2*b^3*(3*a + 8*b + 5*a*Cos[2*(e + f
*x)]))/((a + b)^2*(a + 2*b + a*Cos[2*(e + f*x)])^2))*Sin[2*(e + f*x)])/(8*a^4*f)

Maple [A] (verified)

Time = 4.40 (sec) , antiderivative size = 177, normalized size of antiderivative = 0.88

method result size
derivativedivides \(\frac {\frac {b^{2} \left (\frac {\frac {a b \left (11 a +8 b \right ) \tan \left (f x +e \right )^{3}}{8 a^{2}+16 a b +8 b^{2}}+\frac {\left (13 a +8 b \right ) a \tan \left (f x +e \right )}{8 a +8 b}}{\left (a +b +b \tan \left (f x +e \right )^{2}\right )^{2}}+\frac {\left (35 a^{2}+56 a b +24 b^{2}\right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{8 \left (a^{2}+2 a b +b^{2}\right ) \sqrt {\left (a +b \right ) b}}\right )}{a^{4}}+\frac {\frac {a \tan \left (f x +e \right )}{2+2 \tan \left (f x +e \right )^{2}}+\frac {\left (a -6 b \right ) \arctan \left (\tan \left (f x +e \right )\right )}{2}}{a^{4}}}{f}\) \(177\)
default \(\frac {\frac {b^{2} \left (\frac {\frac {a b \left (11 a +8 b \right ) \tan \left (f x +e \right )^{3}}{8 a^{2}+16 a b +8 b^{2}}+\frac {\left (13 a +8 b \right ) a \tan \left (f x +e \right )}{8 a +8 b}}{\left (a +b +b \tan \left (f x +e \right )^{2}\right )^{2}}+\frac {\left (35 a^{2}+56 a b +24 b^{2}\right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {\left (a +b \right ) b}}\right )}{8 \left (a^{2}+2 a b +b^{2}\right ) \sqrt {\left (a +b \right ) b}}\right )}{a^{4}}+\frac {\frac {a \tan \left (f x +e \right )}{2+2 \tan \left (f x +e \right )^{2}}+\frac {\left (a -6 b \right ) \arctan \left (\tan \left (f x +e \right )\right )}{2}}{a^{4}}}{f}\) \(177\)
risch \(\frac {x}{2 a^{3}}-\frac {3 x b}{a^{4}}-\frac {i {\mathrm e}^{2 i \left (f x +e \right )}}{8 a^{3} f}+\frac {i {\mathrm e}^{-2 i \left (f x +e \right )}}{8 a^{3} f}+\frac {i b^{2} \left (13 a^{3} {\mathrm e}^{6 i \left (f x +e \right )}+40 a^{2} b \,{\mathrm e}^{6 i \left (f x +e \right )}+24 a \,b^{2} {\mathrm e}^{6 i \left (f x +e \right )}+39 a^{3} {\mathrm e}^{4 i \left (f x +e \right )}+134 a^{2} b \,{\mathrm e}^{4 i \left (f x +e \right )}+184 a \,b^{2} {\mathrm e}^{4 i \left (f x +e \right )}+80 b^{3} {\mathrm e}^{4 i \left (f x +e \right )}+39 a^{3} {\mathrm e}^{2 i \left (f x +e \right )}+104 a^{2} b \,{\mathrm e}^{2 i \left (f x +e \right )}+56 a \,b^{2} {\mathrm e}^{2 i \left (f x +e \right )}+13 a^{3}+10 a^{2} b \right )}{4 a^{4} \left (a +b \right )^{2} f \left (a \,{\mathrm e}^{4 i \left (f x +e \right )}+2 a \,{\mathrm e}^{2 i \left (f x +e \right )}+4 b \,{\mathrm e}^{2 i \left (f x +e \right )}+a \right )^{2}}+\frac {35 \sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right ) b}{16 \left (a +b \right )^{3} f \,a^{2}}+\frac {7 \sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right ) b^{2}}{2 \left (a +b \right )^{3} f \,a^{3}}+\frac {3 \sqrt {-\left (a +b \right ) b}\, b^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-\left (a +b \right ) b}-a -2 b}{a}\right )}{2 \left (a +b \right )^{3} f \,a^{4}}-\frac {35 \sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right ) b}{16 \left (a +b \right )^{3} f \,a^{2}}-\frac {7 \sqrt {-\left (a +b \right ) b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right ) b^{2}}{2 \left (a +b \right )^{3} f \,a^{3}}-\frac {3 \sqrt {-\left (a +b \right ) b}\, b^{3} \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-\left (a +b \right ) b}+a +2 b}{a}\right )}{2 \left (a +b \right )^{3} f \,a^{4}}\) \(600\)

[In]

int(cos(f*x+e)^2/(a+b*sec(f*x+e)^2)^3,x,method=_RETURNVERBOSE)

[Out]

1/f*(b^2/a^4*((1/8*a*b*(11*a+8*b)/(a^2+2*a*b+b^2)*tan(f*x+e)^3+1/8*(13*a+8*b)*a/(a+b)*tan(f*x+e))/(a+b+b*tan(f
*x+e)^2)^2+1/8*(35*a^2+56*a*b+24*b^2)/(a^2+2*a*b+b^2)/((a+b)*b)^(1/2)*arctan(b*tan(f*x+e)/((a+b)*b)^(1/2)))+1/
a^4*(1/2*a*tan(f*x+e)/(1+tan(f*x+e)^2)+1/2*(a-6*b)*arctan(tan(f*x+e))))

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 442 vs. \(2 (183) = 366\).

Time = 0.33 (sec) , antiderivative size = 970, normalized size of antiderivative = 4.83 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Too large to display} \]

[In]

integrate(cos(f*x+e)^2/(a+b*sec(f*x+e)^2)^3,x, algorithm="fricas")

[Out]

[1/32*(16*(a^5 - 4*a^4*b - 11*a^3*b^2 - 6*a^2*b^3)*f*x*cos(f*x + e)^4 + 32*(a^4*b - 4*a^3*b^2 - 11*a^2*b^3 - 6
*a*b^4)*f*x*cos(f*x + e)^2 + 16*(a^3*b^2 - 4*a^2*b^3 - 11*a*b^4 - 6*b^5)*f*x + (35*a^2*b^3 + 56*a*b^4 + 24*b^5
 + (35*a^4*b + 56*a^3*b^2 + 24*a^2*b^3)*cos(f*x + e)^4 + 2*(35*a^3*b^2 + 56*a^2*b^3 + 24*a*b^4)*cos(f*x + e)^2
)*sqrt(-b/(a + b))*log(((a^2 + 8*a*b + 8*b^2)*cos(f*x + e)^4 - 2*(3*a*b + 4*b^2)*cos(f*x + e)^2 - 4*((a^2 + 3*
a*b + 2*b^2)*cos(f*x + e)^3 - (a*b + b^2)*cos(f*x + e))*sqrt(-b/(a + b))*sin(f*x + e) + b^2)/(a^2*cos(f*x + e)
^4 + 2*a*b*cos(f*x + e)^2 + b^2)) + 4*(4*(a^5 + 2*a^4*b + a^3*b^2)*cos(f*x + e)^5 + (8*a^4*b + 29*a^3*b^2 + 18
*a^2*b^3)*cos(f*x + e)^3 + (4*a^3*b^2 + 19*a^2*b^3 + 12*a*b^4)*cos(f*x + e))*sin(f*x + e))/((a^8 + 2*a^7*b + a
^6*b^2)*f*cos(f*x + e)^4 + 2*(a^7*b + 2*a^6*b^2 + a^5*b^3)*f*cos(f*x + e)^2 + (a^6*b^2 + 2*a^5*b^3 + a^4*b^4)*
f), 1/16*(8*(a^5 - 4*a^4*b - 11*a^3*b^2 - 6*a^2*b^3)*f*x*cos(f*x + e)^4 + 16*(a^4*b - 4*a^3*b^2 - 11*a^2*b^3 -
 6*a*b^4)*f*x*cos(f*x + e)^2 + 8*(a^3*b^2 - 4*a^2*b^3 - 11*a*b^4 - 6*b^5)*f*x - (35*a^2*b^3 + 56*a*b^4 + 24*b^
5 + (35*a^4*b + 56*a^3*b^2 + 24*a^2*b^3)*cos(f*x + e)^4 + 2*(35*a^3*b^2 + 56*a^2*b^3 + 24*a*b^4)*cos(f*x + e)^
2)*sqrt(b/(a + b))*arctan(1/2*((a + 2*b)*cos(f*x + e)^2 - b)*sqrt(b/(a + b))/(b*cos(f*x + e)*sin(f*x + e))) +
2*(4*(a^5 + 2*a^4*b + a^3*b^2)*cos(f*x + e)^5 + (8*a^4*b + 29*a^3*b^2 + 18*a^2*b^3)*cos(f*x + e)^3 + (4*a^3*b^
2 + 19*a^2*b^3 + 12*a*b^4)*cos(f*x + e))*sin(f*x + e))/((a^8 + 2*a^7*b + a^6*b^2)*f*cos(f*x + e)^4 + 2*(a^7*b
+ 2*a^6*b^2 + a^5*b^3)*f*cos(f*x + e)^2 + (a^6*b^2 + 2*a^5*b^3 + a^4*b^4)*f)]

Sympy [F(-1)]

Timed out. \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Timed out} \]

[In]

integrate(cos(f*x+e)**2/(a+b*sec(f*x+e)**2)**3,x)

[Out]

Timed out

Maxima [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 338, normalized size of antiderivative = 1.68 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\frac {{\left (35 \, a^{2} b^{2} + 56 \, a b^{3} + 24 \, b^{4}\right )} \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {{\left (a + b\right )} b}}\right )}{{\left (a^{6} + 2 \, a^{5} b + a^{4} b^{2}\right )} \sqrt {{\left (a + b\right )} b}} + \frac {{\left (4 \, a^{2} b^{2} + 19 \, a b^{3} + 12 \, b^{4}\right )} \tan \left (f x + e\right )^{5} + {\left (8 \, a^{3} b + 37 \, a^{2} b^{2} + 56 \, a b^{3} + 24 \, b^{4}\right )} \tan \left (f x + e\right )^{3} + {\left (4 \, a^{4} + 16 \, a^{3} b + 37 \, a^{2} b^{2} + 37 \, a b^{3} + 12 \, b^{4}\right )} \tan \left (f x + e\right )}{a^{7} + 4 \, a^{6} b + 6 \, a^{5} b^{2} + 4 \, a^{4} b^{3} + a^{3} b^{4} + {\left (a^{5} b^{2} + 2 \, a^{4} b^{3} + a^{3} b^{4}\right )} \tan \left (f x + e\right )^{6} + {\left (2 \, a^{6} b + 7 \, a^{5} b^{2} + 8 \, a^{4} b^{3} + 3 \, a^{3} b^{4}\right )} \tan \left (f x + e\right )^{4} + {\left (a^{7} + 6 \, a^{6} b + 12 \, a^{5} b^{2} + 10 \, a^{4} b^{3} + 3 \, a^{3} b^{4}\right )} \tan \left (f x + e\right )^{2}} + \frac {4 \, {\left (f x + e\right )} {\left (a - 6 \, b\right )}}{a^{4}}}{8 \, f} \]

[In]

integrate(cos(f*x+e)^2/(a+b*sec(f*x+e)^2)^3,x, algorithm="maxima")

[Out]

1/8*((35*a^2*b^2 + 56*a*b^3 + 24*b^4)*arctan(b*tan(f*x + e)/sqrt((a + b)*b))/((a^6 + 2*a^5*b + a^4*b^2)*sqrt((
a + b)*b)) + ((4*a^2*b^2 + 19*a*b^3 + 12*b^4)*tan(f*x + e)^5 + (8*a^3*b + 37*a^2*b^2 + 56*a*b^3 + 24*b^4)*tan(
f*x + e)^3 + (4*a^4 + 16*a^3*b + 37*a^2*b^2 + 37*a*b^3 + 12*b^4)*tan(f*x + e))/(a^7 + 4*a^6*b + 6*a^5*b^2 + 4*
a^4*b^3 + a^3*b^4 + (a^5*b^2 + 2*a^4*b^3 + a^3*b^4)*tan(f*x + e)^6 + (2*a^6*b + 7*a^5*b^2 + 8*a^4*b^3 + 3*a^3*
b^4)*tan(f*x + e)^4 + (a^7 + 6*a^6*b + 12*a^5*b^2 + 10*a^4*b^3 + 3*a^3*b^4)*tan(f*x + e)^2) + 4*(f*x + e)*(a -
 6*b)/a^4)/f

Giac [A] (verification not implemented)

none

Time = 0.34 (sec) , antiderivative size = 228, normalized size of antiderivative = 1.13 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\frac {\frac {{\left (35 \, a^{2} b^{2} + 56 \, a b^{3} + 24 \, b^{4}\right )} {\left (\pi \left \lfloor \frac {f x + e}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b + b^{2}}}\right )\right )}}{{\left (a^{6} + 2 \, a^{5} b + a^{4} b^{2}\right )} \sqrt {a b + b^{2}}} + \frac {11 \, a b^{3} \tan \left (f x + e\right )^{3} + 8 \, b^{4} \tan \left (f x + e\right )^{3} + 13 \, a^{2} b^{2} \tan \left (f x + e\right ) + 21 \, a b^{3} \tan \left (f x + e\right ) + 8 \, b^{4} \tan \left (f x + e\right )}{{\left (a^{5} + 2 \, a^{4} b + a^{3} b^{2}\right )} {\left (b \tan \left (f x + e\right )^{2} + a + b\right )}^{2}} + \frac {4 \, {\left (f x + e\right )} {\left (a - 6 \, b\right )}}{a^{4}} + \frac {4 \, \tan \left (f x + e\right )}{{\left (\tan \left (f x + e\right )^{2} + 1\right )} a^{3}}}{8 \, f} \]

[In]

integrate(cos(f*x+e)^2/(a+b*sec(f*x+e)^2)^3,x, algorithm="giac")

[Out]

1/8*((35*a^2*b^2 + 56*a*b^3 + 24*b^4)*(pi*floor((f*x + e)/pi + 1/2)*sgn(b) + arctan(b*tan(f*x + e)/sqrt(a*b +
b^2)))/((a^6 + 2*a^5*b + a^4*b^2)*sqrt(a*b + b^2)) + (11*a*b^3*tan(f*x + e)^3 + 8*b^4*tan(f*x + e)^3 + 13*a^2*
b^2*tan(f*x + e) + 21*a*b^3*tan(f*x + e) + 8*b^4*tan(f*x + e))/((a^5 + 2*a^4*b + a^3*b^2)*(b*tan(f*x + e)^2 +
a + b)^2) + 4*(f*x + e)*(a - 6*b)/a^4 + 4*tan(f*x + e)/((tan(f*x + e)^2 + 1)*a^3))/f

Mupad [B] (verification not implemented)

Time = 24.10 (sec) , antiderivative size = 3708, normalized size of antiderivative = 18.45 \[ \int \frac {\cos ^2(e+f x)}{\left (a+b \sec ^2(e+f x)\right )^3} \, dx=\text {Too large to display} \]

[In]

int(cos(e + f*x)^2/(a + b/cos(e + f*x)^2)^3,x)

[Out]

((tan(e + f*x)^5*(19*a*b^3 + 12*b^4 + 4*a^2*b^2))/(8*a^3*(a + b)^2) + (tan(e + f*x)*(25*a*b^2 + 12*a^2*b + 4*a
^3 + 12*b^3))/(8*a^3*(a + b)) + (b*tan(e + f*x)^3*(56*a*b^2 + 37*a^2*b + 8*a^3 + 24*b^3))/(8*a^3*(a + b)^2))/(
f*(2*a*b + tan(e + f*x)^2*(4*a*b + a^2 + 3*b^2) + a^2 + b^2 + tan(e + f*x)^4*(2*a*b + 3*b^2) + b^2*tan(e + f*x
)^6)) + (atan(((((((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a
^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) - (tan(e + f*x)*(a*1i - b*6i)*(512*a^8*b^7 + 2304*a^9*b^6 +
4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(128*a^4*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3
+ 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4) - (tan(e + f*x)*(4800*a*b^8 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 + 1
129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6i
)*1i)/(4*a^4) - (((((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*
a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) + (tan(e + f*x)*(a*1i - b*6i)*(512*a^8*b^7 + 2304*a^9*b^6 +
 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(128*a^4*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3
 + 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4) + (tan(e + f*x)*(4800*a*b^8 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 +
1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6
i)*1i)/(4*a^4))/(((405*a*b^8)/4 + 27*b^9 + (261*a^2*b^7)/2 + (1877*a^3*b^6)/32 - (49*a^4*b^5)/64 - (35*a^5*b^4
)/16)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) + (((((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 +
(45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) - (tan(e + f*
x)*(a*1i - b*6i)*(512*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/
(128*a^4*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4) - (tan(e + f*x)*(4800*a*b
^8 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 + 1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 +
a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4) + (((((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (4
5*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) + (tan(e + f*x)
*(a*1i - b*6i)*(512*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(1
28*a^4*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4) + (tan(e + f*x)*(4800*a*b^8
 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 + 1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^
6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)))*(a*1i - b*6i))/(4*a^4)))*(a*1i - b*6i)*1i)/(2*a^4*f) - (atan(((((tan(e + f*x)
*(4800*a*b^8 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 + 1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b
 + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)) - (((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (45*a^11*b^4)/2 +
2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) - (tan(e + f*x)*(-b^3*(a + b)^5
)^(1/2)*(56*a*b + 35*a^2 + 24*b^2)*(512*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3
 + 256*a^13*b^2))/(512*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4
 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2))/(16*(5*a^8*b + a^9 + a^4*b^5
+ 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2)*1i)/(16*(5*a^8*b +
a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)) + (((tan(e + f*x)*(4800*a*b^8 + 1152*b^9 + 7520*a^2*b^7
+ 5136*a^3*b^6 + 1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b
^2)) + (((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*b + a^
13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) + (tan(e + f*x)*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2)*(512
*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(512*(4*a^9*b + a^10
+ a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b^3*(a
+ b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2))/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2))
)*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2)*1i)/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3
+ 10*a^7*b^2)))/(((405*a*b^8)/4 + 27*b^9 + (261*a^2*b^7)/2 + (1877*a^3*b^6)/32 - (49*a^4*b^5)/64 - (35*a^5*b^4
)/16)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) - (((tan(e + f*x)*(4800*a*b^8 + 1152*b^9 + 7520*a^
2*b^7 + 5136*a^3*b^6 + 1129*a^4*b^5 - 128*a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6
*a^8*b^2)) - (((6*a^8*b^7 + (49*a^9*b^6)/2 + 37*a^10*b^5 + (45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*
b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b^2) - (tan(e + f*x)*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2
)*(512*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(512*(4*a^9*b +
 a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b
^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2))/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7
*b^2)))*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2))/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b
^3 + 10*a^7*b^2)) + (((tan(e + f*x)*(4800*a*b^8 + 1152*b^9 + 7520*a^2*b^7 + 5136*a^3*b^6 + 1129*a^4*b^5 - 128*
a^5*b^4 + 16*a^6*b^3))/(32*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)) + (((6*a^8*b^7 + (49*a^9*b^6)/2
 + 37*a^10*b^5 + (45*a^11*b^4)/2 + 2*a^12*b^3 - 2*a^13*b^2)/(4*a^12*b + a^13 + a^9*b^4 + 4*a^10*b^3 + 6*a^11*b
^2) + (tan(e + f*x)*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*b^2)*(512*a^8*b^7 + 2304*a^9*b^6 + 4096*a^10*
b^5 + 3584*a^11*b^4 + 1536*a^12*b^3 + 256*a^13*b^2))/(512*(4*a^9*b + a^10 + a^6*b^4 + 4*a^7*b^3 + 6*a^8*b^2)*(
5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 35*a^2 + 24*
b^2))/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2)))*(-b^3*(a + b)^5)^(1/2)*(56*a*b + 3
5*a^2 + 24*b^2))/(16*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2))))*(-b^3*(a + b)^5)^(1/2)
*(56*a*b + 35*a^2 + 24*b^2)*1i)/(8*f*(5*a^8*b + a^9 + a^4*b^5 + 5*a^5*b^4 + 10*a^6*b^3 + 10*a^7*b^2))